ID: 628300a9
(SAT Suite Question Bank > Find Questions > Assessment: SAT + Test: Math + Domain: Algebra)
Comment: Organize and conquer.
Method 1: Because there is no restriction that says that both of experiments A and B must be conducted, we can effectively ignore B and focus on A, the one to which the unknown x is attached. If experiment A requires 6 teaspoons of salt and there can be no more than 5 stations, that means there can be no more than 6 * 5, or 30 teaspoons used. Check the answer choices to eliminate anything possible, plugging in 5 for x.
A. 5(5) = 25 X
B. 10(5) = 50 X
C. 2(5) + 20 = 30 √
D. 10(5) + 20 = 70 X
The correct answer is (C), and the solution takes less than 30 seconds as long as you have a decent grasp of arithmetic. Had two answer choices worked, you could easily drop x from 5 to, say, 4 and think of the other station as one that used 4 teaspoons of salt (for experiment B). Only (C) would yield 28, the same as 6 * 4 + 4 * 1 (6 tsp * 4 stations + 4 tsp * 1 station).
Method 2: With a little creativity, you can put Desmos to use. Let x be less than or equal 5, then test the answer choices.
Method 3: Your math teacher or textbook might work through the following solution. If there are 5 stations and each will be set up for experiment A or B, then we know that A + B = 5. If, as the question stem tells us, x stations are set up for A, then we can alter our equation into an expression:
(x) + (5 - x)
To track teaspoons of salt, if each A setup requires 6 teaspoons and each B setup requires 4 teaspoons, then we now have a way to derive the answer.
6(x) + 4(5 - x) = total teaspoons
6x + 20 - 4x = total teaspoons
2x + 20 = total teaspoons
The correct answer is (C).
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